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6x^2+4x-4=6
We move all terms to the left:
6x^2+4x-4-(6)=0
We add all the numbers together, and all the variables
6x^2+4x-10=0
a = 6; b = 4; c = -10;
Δ = b2-4ac
Δ = 42-4·6·(-10)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-16}{2*6}=\frac{-20}{12} =-1+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+16}{2*6}=\frac{12}{12} =1 $
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